3x^2+60x-70=0

Solution for 3x^2+60x-70=0 equation:

3x^2+60x-70=0

a = 3; b = 60; c = -70;
Δ = b2-4ac
Δ = 602-4·3·(-70)
Δ = 4440
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{4440}=\sqrt{4*1110}=\sqrt{4}*\sqrt{1110}=2\sqrt{1110}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(60)-2\sqrt{1110}}{2*3}=\frac{-60-2\sqrt{1110}}{6}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(60)+2\sqrt{1110}}{2*3}=\frac{-60+2\sqrt{1110}}{6}
$